1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | var GMT_TIMES = [[2019,[2019,02,31],[2019,9,27]],[2020,[2020,02,29],[2020,9,25]]]; function gmtSummerAndWinterTime(){ var today = new Date(); var thisYear = today.getFullYear(); var todayNumber = today.getTime(); for(var g=0;g<GMT_TIMES.length;g++){ var gmtTijd = GMT_TIMES[g]; var dateSummerTimeNumber = new Date(GMT_TIMES[1][0],GMT_TIMES[1][1],GMT_TIMES[1][2]).getTime(); var dateWinterTimeNumber = new Date(GMT_TIMES[2][0],GMT_TIMES[2][1],GMT_TIMES[2][2]).getTime(); if(GMT_TIMES[0] == thisYear && dateSummerTimeNumber < todayNumber && todayNumber < dateWinterTimeNumber){ var gmt = "GMT+2"; return gmt; } else{ gmt = "GMT+1"; return gmt } } } |
The
Session
thing is so much easier.'Problem' with
formatDate(date,timeZone,format)
in combination with SimpleDateFormat class
is that it is in English. There are people using other languages than English.The Google Language Service could be used to solve the 'problem'.
I prefer the following 'solution'.
1 2 3 4 5 6 7 8 | function getWeekDayName(){ var weekdayNames = ["zondag","maandag","dinsdag","woensdag","donderdag","vrijdag","zaterdag"]; var today = new Date(); var timeZone = Session.getScriptTimeZone(); var weekdayNumber = Utilities.formatDate(today,timeZone,"u"); var weekdayName = weekdayNames[weekdayNumber]; Logger.log('Weekday name is: ' + weekdayName); } |
Resources:
Get weekday name from a date, Phil Bainbridge, 2 december 2019
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